GRAPH 3
PRACTICE 6
1) For the cubic graph (green), x is between -2 and 1
2) For the translated cubic, (black), x is between 4 and 7
3) For the exponential graph (purple), x is between 0 and 3
4) For the translated exponential graph (purple), x is between 6 and 9
5) For the positive (concave up) parabola (blue), x is between -3 and -1
6) For the translated positive (concave up) parabola (red), x is between 3 and 5
7) For the second parabola (concave down, green) x is between 2 and 4
8) For the translated negative parabola (concave down, blue), x is between 8 and 10
Merit:
Transform all parts of the original image horizontally and vertically with no overlap and state their equations.
"I have moved the original image 6 places to the right and 1 place down. For example, this changes the original equation of the first parabola as follows:
y = 2(x + 2)^2 + 8 for x values between -3 and -1
The number inside the brackets has decreased by 6 and moves the image to the right. The number outside of the brackets has decreased by 1 and this lowers the image by 1 place.
The domains have increased by 6".
Transform all parts of the original image horizontally and vertically with no overlap and state their equations.
"I have moved the original image 6 places to the right and 1 place down. For example, this changes the original equation of the first parabola as follows:
y = 2(x + 2)^2 + 8 for x values between -3 and -1
The number inside the brackets has decreased by 6 and moves the image to the right. The number outside of the brackets has decreased by 1 and this lowers the image by 1 place.
The domains have increased by 6".
Excellence:
The following equations describe how the original image is translated horizontally by a factor of 'h' and vertically by a factor of 'v'
1) For the cubic graph (green), y = (x - h)^3 + v
2) For the exponential graph (purple), y = 2^(x - h) - 1 + v
3) For the first positive (concave up) parabola (blue), y = 2(x + 2 - h)^2 + 8 + v
4) For the second inverted (concave down) parabola (green), y = -2(x - 3 - h)^2 + 7 + v